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x^2+5x+2x+4+x=180
We move all terms to the left:
x^2+5x+2x+4+x-(180)=0
We add all the numbers together, and all the variables
x^2+8x-176=0
a = 1; b = 8; c = -176;
Δ = b2-4ac
Δ = 82-4·1·(-176)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-16\sqrt{3}}{2*1}=\frac{-8-16\sqrt{3}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+16\sqrt{3}}{2*1}=\frac{-8+16\sqrt{3}}{2} $
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